There are n cities. Some of them are connected, while some are not. If city a is connected directly with city b, and city b is connected directly with city c, then city a is connected indirectly with city c.
A province is a group of directly or indirectly connected cities and no other cities outside of the group.
You are given an n x n matrix isConnected where isConnected[i][j] = 1 if the ith city and the jth city are directly connected, and isConnected[i][j] = 0 otherwise.
Return the total number of provinces.
Union Find Approach:
Key Insight: The number of provinces equals the number of disjoint sets after processing all connections.
isConnected = [[1,1,0],[1,1,0],[0,0,1]]2isConnected = [[1,0,0],[0,1,0],[0,0,1]]3isConnected = [[1,1,1],[1,1,1],[1,1,1]]11 <= n <= 200n == isConnected.lengthn == isConnected[i].lengthisConnected[i][j] is 1 or 0isConnected[i][i] == 1isConnected[i][j] == isConnected[j][i]Click "Run" to execute your code against test cases
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